-35v^2-9v+2=0

Solution for -35v^2-9v+2=0 equation:

-35v^2-9v+2=0

a = -35; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·(-35)·2
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-19}{2*-35}=\frac{-10}{-70}
=1/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+19}{2*-35}=\frac{28}{-70}
=-2/5
$